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Merge branch 'master' of ssh://github.com/vincenthz/hs-tls

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Vincent Hanquez 2014-04-18 09:35:29 +01:00
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README.md
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@ -1,7 +1,7 @@
haskell TLS haskell TLS
=========== ===========
This library provide native Haskell TLS and SSL protocol implementation for server and client. This library provides native Haskell TLS and SSL protocol implementation for server and client.
Description Description
----------- -----------
@ -13,13 +13,13 @@ type system, high level constructions and common Haskell features.
Features Features
-------- --------
* tiny code base (more than 20 times smaller than openSSL, and 10 times smaller than gnuTLS) * tiny codebase (more than 20 times smaller than OpenSSL, and 10 times smaller than gnuTLS)
* client certificates. * client certificates
* permissive license: BSD3. * permissive license: BSD3
* supported versions: SSL3, TLS1.0, TLS1.1, TLS1.2. * supported versions: SSL3, TLS1.0, TLS1.1, TLS1.2
* key exchange supported: RSA, DHE-RSA, DHE-DSS. * key exchange supported: RSA, DHE-RSA, DHE-DSS
* bulk algorithm supported: any stream or block ciphers. * bulk algorithm supported: any stream or block ciphers
* supported extensions: secure renegociation, next protocol negotiation (draft 2), server name indication. * supported extensions: secure renegociation, next protocol negotiation (draft 2), server name indication
Common Issues Common Issues
============= =============
@ -34,7 +34,7 @@ retrieve the certificate chained used.
tls-retrievecertificate -d <destination> -p <port> -v -c tls-retrievecertificate -d <destination> -p <port> -v -c
As an output it will print every certificates in the chain and will gives the issuer and subjects of each. As an output it will print every certificate in the chain and will give the issuer and subjects of each.
It creates a chain where issuer of certificate is the subject of the next certificate part of the chain: It creates a chain where issuer of certificate is the subject of the next certificate part of the chain:
(subject #1, issuer #2) -> (subject #2, issuer #3) -> (subject #3, issuer #3) (subject #1, issuer #2) -> (subject #2, issuer #3) -> (subject #3, issuer #3)